I mean, I guess there’s safety in numbers on floor 3 at least
That would leave Marl alone with a large crab mind you.
I mean, I guess there’s safety in numbers on floor 3 at least
That would leave Marl alone with a large crab mind you.
Ok
I’m requesting groups of 2 unless I’m in the group, in which case 3
Does he have both actions?
Who’s currently on floor 3?
I’m fine with that, and being part of your trio.
So if Met is dead, then it’s
2, 2, 2, 3?
Yes
Yup.
Or 3 3 3.
Ngl this game is fucking thrilling
Unless you want me to be going solo and randomly appearing on floors to check people
Which do you think would be better?
All 3s or 3 groups of 2 and 1 group of 3?
The one I recommended
You’d be like the ticket inspector that hops on the bus on the one day I forget my buspass
Lol yep
I’m trying to theory this
9 of us left, right?
So in theory if we go 1 (Marg), 2, 3, 3, this should work
On the principle that there may still be untrustworthies about, and I’m thinking a maximum of 2 at this point, with Marg acting as trusted cop this would work 100% of the time
I’ve been waiting to implement this strategy since I first saw it in a TedEd Riddle
I did, didn’t find it