It would still have the same colour as Classic, even if we were to ignore the theme of opposite thing.
If we go for the colour thing though, nice and smart are not the same.
Nice is red.
Smart is blue with red dots.
If we assume everything to do with red is bad, then that would be 6 boxes.
With only Classic, Funny, Bad, Good being good boxes.
I did said that I think the bad box are completely random.
You only need to pick a pattern and theme for the good one and everything else is bad.
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Based on Mole saying before that Wazza will not get a turn, we only need to choose 4 correct boxes.
I did not realise this before because the way which this floor sounded is that we have to avoid choosing 4 bad boxes.
I assumed this would mean there are only 4 or 5 bad boxes as all 8 of us would have to go. If there were 5 bad, there would be 5 good so it could be 5 good, 3 bad for a success.
Since it seems that is not the case, we can consider the possibility of there being 6 bad boxes now.
More than that and one side would have an advantage, if anyone were to have an advantage, it’s going to be The Saboteur.
GDI Mole, you posted it after the big post which is all I paid attention to. Oh well.
My issue atm is just figuring out who the traitor is while doing all this because I am like fairly sure I am trapped otherwise.
I admitted to somewhat know the show. I have been the most active contributor, despite being wrong.
It is not great.
There are 3 worlds.
4 good, 6 bad
5 good, 5 bad
6 good, 4 bad
All of these worlds atm are possible.
I think it is more likely that than the other way around because as you said the Saboteur is at an advantage.
It is highly likely they know which are good and which are bad, so their turn is basically a free bad one if they need it.
The only person this would not apply to is Wazza because of being the last turn person.
Based on what I said, in likelihood it is either 5 of each. Or 6 good, 4 bad.
I doubt is it 4 good, 6 bad since saboteur already has an info advantage.
True. But also don’t forget that The Unfortunate have majority, as well as another chance to find The Saboteur if they fail the challenge.
This is true, but, what better way for them to remain undetected than there being 6 bad and only 4 good boxes?
I know this is too early but everything point towards PKR in every possible way, you could say he is the perfect candidate for the most likely person to be The Saboteur. We can discuss this later but right now I highly doubt he would be that obvious.
Also it’s probably 5 good 5 bad anyway so I think we should focus on solving the puzzle instead of arguing how likely it is for we to open the gift box just for there to be a sock inside.
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