If the pattern gets reset every time we fail and there’s only one good flower in each, we would have approximately 1/256 chance… lol. I think this can be ruled out.
So either:
The pattern gets reset upon failure and there are at least 2 good flowers each round
The pattern does not get reset, and there is most likely 1 good flower each round.
but the pattern could be that you have to place all 4.
Which means you would have to place the Black Flower last and then she has every flower.
Otherwise, I can’t see how this can make sense.
Actually, we have 5 rounds instead of 4. The colour pattern might not be it after all, because then the remaining flower should be random and it doesn’t make sense in an otherwise functional pattern.
If 2 is the case then the pattern is just Blue>White>Red right? I’m just making sure I understand what you mean by pattern not reseting
That is what I am thinking.
I am against using the black flower because the last time I used it we got hard reset.
That and the fact that it does not really make a pattern per se whereas my 1, 2, 3, 2, 1 does.
Because the order resets everytime, that’s what I see. Which yes, would be rigged.
E.G:
The First one was Blue -> Red/White -> Red/Black/White -> Red/Black/White
The Second one, the one currently, would be White -> Red -> Blue -> Black
I just don’t know how on earth we could ever logically reach the 1, 2, 3, 2, 1 conclusion.
Because pattern recognition from the first round.
We won by using double letters.
This time it is doubling the colours but putting it into order like that too.
If we were following that logic, why wouldn’t it be 1, 2, 2, 1 or 1, 1, 2, 2 or 1, 2, 1, 2 and not 1, 2, 3, 2, 1.
Good:
Classic
Good
Funny
Silly
Cool
Bad:
Smart
Nice
Dumb
Lame
Bad
This is what you’re getting at and I know you are, but it doesn’t make sense.
I really think this is a reach. Like I get what you’re trying to say, I just don’t think we could be expected to conclude that.
As we very clearly already placed 3 different ones in positions 1, 2, 3.
In order to make a pattern you would need 4, 5. Which, we only have 4 colours IIRC so that is an error.
Or 2, 1 to create one that is the same either way it is read.
It goes based on colour RGB (I don’t know the proper term for what I’m saying)
Basically:
White
Red
Blue
Black
Would be the order (It would make sense) and the reason we failed the first one is because we placed down another flower which triggered it to end (Thus, negative effect for the non-Saboteurs as such)
